Question

find $\frac{dy}{dx}$
y = - 6x^{\frac{1}{5}}$\frac{dy}{dx}=square$

Explanation:

Step1: Apply power - rule

$y = - 6x^{\frac{1}{5}}$, $\frac{dy}{dx}=-6\times\frac{1}{5}x^{\frac{1}{5}-1}$

Step2: Simplify the exponent

$\frac{dy}{dx}=-\frac{6}{5}x^{-\frac{4}{5}}$

Answer:

$-\frac{6}{5}x^{-\frac{4}{5}}$