QUESTION IMAGE
Question
find the distance between the two points in simplest radical form.
Response
- First, assume the two - point formula:
- The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Let the first point be \((2,1)\) and the second point be \((4, - 3)\).
- Then, identify the values of \(x_1,x_2,y_1,y_2\):
- Here, \(x_1 = 2,y_1 = 1,x_2 = 4,y_2=-3\).
- Next, calculate \((x_2 - x_1)\) and \((y_2 - y_1)\):
- \(x_2 - x_1=4 - 2=2\).
- \(y_2 - y_1=-3 - 1=-4\).
- Then, calculate \((x_2 - x_1)^2+(y_2 - y_1)^2\):
- \((x_2 - x_1)^2+(y_2 - y_1)^2=2^2+( - 4)^2\).
- \(2^2+( - 4)^2 = 4 + 16=20\).
- Finally, find the distance \(d\):
- \(d=\sqrt{20}\).
- Simplify \(\sqrt{20}=\sqrt{4\times5}=2\sqrt{5}\).
Step1: Identify distance formula
\(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)
Step2: Determine point - coordinates
Let \((x_1,y_1)=(2,1)\) and \((x_2,y_2)=(4, - 3)\)
Step3: Calculate \(x_2 - x_1\) and \(y_2 - y_1\)
\(x_2 - x_1 = 2\), \(y_2 - y_1=-4\)
Step4: Calculate \((x_2 - x_1)^2+(y_2 - y_1)^2\)
\((x_2 - x_1)^2+(y_2 - y_1)^2=4 + 16 = 20\)
Step5: Simplify the square - root
\(d=\sqrt{20}=2\sqrt{5}\)
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\(2\sqrt{5}\)