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QUESTION IMAGE

find the distance between the two points in simplest radical form.

Question

find the distance between the two points in simplest radical form.

Explanation:

Response
  1. First, assume the two - point formula:
  • The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Let the first point be \((2,1)\) and the second point be \((4, - 3)\).
  1. Then, identify the values of \(x_1,x_2,y_1,y_2\):
  • Here, \(x_1 = 2,y_1 = 1,x_2 = 4,y_2=-3\).
  1. Next, calculate \((x_2 - x_1)\) and \((y_2 - y_1)\):
  • \(x_2 - x_1=4 - 2=2\).
  • \(y_2 - y_1=-3 - 1=-4\).
  1. Then, calculate \((x_2 - x_1)^2+(y_2 - y_1)^2\):
  • \((x_2 - x_1)^2+(y_2 - y_1)^2=2^2+( - 4)^2\).
  • \(2^2+( - 4)^2 = 4 + 16=20\).
  1. Finally, find the distance \(d\):
  • \(d=\sqrt{20}\).
  • Simplify \(\sqrt{20}=\sqrt{4\times5}=2\sqrt{5}\).

Step1: Identify distance formula

\(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

Step2: Determine point - coordinates

Let \((x_1,y_1)=(2,1)\) and \((x_2,y_2)=(4, - 3)\)

Step3: Calculate \(x_2 - x_1\) and \(y_2 - y_1\)

\(x_2 - x_1 = 2\), \(y_2 - y_1=-4\)

Step4: Calculate \((x_2 - x_1)^2+(y_2 - y_1)^2\)

\((x_2 - x_1)^2+(y_2 - y_1)^2=4 + 16 = 20\)

Step5: Simplify the square - root

\(d=\sqrt{20}=2\sqrt{5}\)

Answer:

\(2\sqrt{5}\)