Question

find the inverse of the equation $y = \sqrt{x} + 8LXB0\bigcirc y=(x + 8)^2LXB1\bigcirc y=x^2 - 8$

Explanation:

Step1: Swap x and y variables

$x = \sqrt{y} + 8$

Step2: Isolate the square root term

$x - 8 = \sqrt{y}$

Step3: Square both sides to solve for y

$(x - 8)^2 = y$

Answer:

$y=(x - 8)^2$