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find the product. 9,488 × 6 over the last 8 years, mr. rodriguez has co…

Question

find the product.
9,488 × 6

over the last 8 years, mr. rodriguez has collected 4,376 baseball cards. if he collected the same number of cards each year, how many did he collect in 1 year?

Explanation:

Response
First Problem: Find the Product of \( 9,488 \times 6 \)

Step 1: Multiply the units digit

Multiply 8 (units digit of 9488) by 6: \( 8 \times 6 = 48 \). Write down 8 and carry over 4.

Step 2: Multiply the tens digit

Multiply 8 (tens digit of 9488) by 6: \( 8 \times 6 = 48 \). Add the carried over 4: \( 48 + 4 = 52 \). Write down 2 and carry over 5.

Step 3: Multiply the hundreds digit

Multiply 4 (hundreds digit of 9488) by 6: \( 4 \times 6 = 24 \). Add the carried over 5: \( 24 + 5 = 29 \). Write down 9 and carry over 2.

Step 4: Multiply the thousands digit

Multiply 9 (thousands digit of 9488) by 6: \( 9 \times 6 = 54 \). Add the carried over 2: \( 54 + 2 = 56 \). Write down 56.

Step 5: Combine the results

Combining the results from each step, we get \( 9488 \times 6 = 56928 \). (Note: The handwritten answer in the image seems incorrect; the correct product is calculated as above.)

To find the number of cards collected per year, we divide the total number of cards (4,376) by the number of years (8), since he collected the same number each year.

Step 1: Set up the division

We need to calculate \( \frac{4376}{8} \).

Step 2: Perform the division

  • 8 goes into 43 five times ( \( 5 \times 8 = 40 \) ), subtract 40 from 43 to get 3.
  • Bring down the 7 to make 37. 8 goes into 37 four times ( \( 4 \times 8 = 32 \) ), subtract 32 from 37 to get 5.
  • Bring down the 6 to make 56. 8 goes into 56 seven times ( \( 7 \times 8 = 56 \) ), subtract 56 from 56 to get 0.

So, \( 4376 \div 8 = 547 \).

Answer:

\( 56928 \)

Second Problem: Mr. Rodriguez's Baseball Cards