Question

if $f(x) = 4x + 3$ and $g(x) = 2x - 1$, to find $(g \circ f)(6)$
question 4 2 pts
if $f(x) = x + 3$, $g(x) = 2x$, and $h(x) = x^2$
to find $h(f(-5))$

Explanation:

Step1: Solve $(g \circ f)(6)$: Compute $f(6)$

$f(6) = 4(6) + 3 = 24 + 3 = 27$

Step2: Substitute $f(6)$ into $g(x)$

$g(f(6)) = g(27) = 2(27) - 1 = 54 - 1 = 53$

Step3: Solve $h(f(-5))$: Compute $f(-5)$

$f(-5) = (-5) + 3 = -2$

Step4: Substitute $f(-5)$ into $h(x)$

$h(f(-5)) = h(-2) = (-2)^2 = 4$

Answer:

$(g \circ f)(6) = 53$
$h(f(-5)) = 4$