Question

find the real solution(s) of the equation $x^{5} = -48$. round your answer(s) to two decimal places.
$x \approx \square$

Explanation:

Step1: Isolate x via root operation

To solve $x^5=-48$, take the 5th root of both sides:
$$x = (-48)^{\frac{1}{5}}$$

Step2: Calculate and round to 2 decimals

Compute the value:
$$(-48)^{\frac{1}{5}} \approx -2.17$$

Answer:

$x \approx -2.17$