Question

find $2h(-7) + 2f(-2)$ in simplified form.

$f(x)$

$g(x) = -x^2 + x - 1$

$x$	$h(x)$
$-8$	$10$
$3$	$-7$
$-7$	$8$

Explanation:

Step1: Find $h(-7)$ from table

From the table, when $x=-7$, $h(-7)=8$.

Step2: Calculate $2h(-7)$

$2h(-7)=2\times8=16$

Step3: Find equation of $f(x)$

The line $f(x)$ has y-intercept $b=4$, slope $m=\frac{4-0}{0-(-4)}=1$. So $f(x)=x+4$.

Step4: Calculate $f(-2)$

$f(-2)=-2+4=2$

Step5: Calculate $2f(-2)$

$2f(-2)=2\times2=4$

Step6: Sum the two results

$2h(-7)+2f(-2)=16+4$

Answer:

20