Question

find the vertical asymptotes (if any) of the graph of the function. (enter your answe
f(x)=\frac{6}{x^{2}+x - 2}
x = 1 \times

Explanation:

Step1: Factor denominator

\( x^2 + x - 2 = (x + 2)(x - 1) \)

Step2: Solve denominator=0

\( (x + 2)(x - 1) = 0 \implies x = -2, 1 \)

Step3: Check numerator not zero

Numerator=6≠0, so asymptotes at roots.

Answer:

x = -2, x = 1