Question

the functions f and g are defined as follows.
$f(x) = -3x^3 - 2$
$g(x) = -3x + 4$
find $f(-3)$ and $g(6)$.
simplify your answers as much as possible.
$f(-3) = \square$
$g(6) = \square$

Explanation:

Step1: Substitute $x=-3$ into $f(x)$

$f(-3) = -3(-3)^3 - 2$

Step2: Calculate the cubic term first

$(-3)^3 = -27$, so $-3(-27) = 81$

Step3: Simplify to find $f(-3)$

$f(-3) = 81 - 2 = 79$

Step4: Substitute $x=6$ into $g(x)$

$g(6) = -3(6) + 4$

Step5: Calculate the product then simplify

$-3(6) = -18$, so $g(6) = -18 + 4 = -14$

Answer:

$f(-3) = 79$
$g(6) = -14$