Question

given that $f(x)=6x + 7$ and $g(x)=x^3$, find $(f \circ g)(-2).$

$(f \circ g)(-2)=\square$

Explanation:

Step1: Compute $g(-2)$

$g(-2) = (-2)^3 = -8$

Step2: Substitute into $f(x)$

$f(g(-2)) = 6(-8) + 7$

Step3: Calculate final value

$6(-8) + 7 = -48 + 7 = -41$

Answer:

$-41$