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given: $y = 2x^2 - 4x + 1$ solve for $y$ when $x = -2$

Question

given: $y = 2x^2 - 4x + 1$
solve for $y$ when $x = -2$

Explanation:

Step1: Substitute $x=-2$ into equation

$y=2(-2)^2 - 4(-2) + 1$

Step2: Calculate exponents first

$(-2)^2=4$, so $y=2\times4 - 4(-2) + 1$

Step3: Perform multiplication operations

$2\times4=8$, $-4(-2)=8$, so $y=8 + 8 + 1$

Step4: Sum the values

$8+8+1=17$

Answer:

$17$