QUESTION IMAGE
Question
graph the following equations
equation 1: ( y = x + 2 )
equation 2: ( y = -2x - 4 )
equation 3: ( y = \frac{2}{3}x )
equation 4: ( y = -\frac{1}{4}x + 3 )
for Graphing Linear Equations (Using Slope - Intercept Form \(y = mx + b\), where \(m\) is slope, \(b\) is y - intercept)
Equation 1: \(y=x + 2\)
Step 1: Identify slope (\(m\)) and y - intercept (\(b\))
For \(y=x + 2\), comparing with \(y = mx + b\), we have \(m = 1\) (slope) and \(b=2\) (y - intercept).
Step 2: Plot the y - intercept
The y - intercept is at the point \((0,2)\). So we mark the point \((0,2)\) on the coordinate plane.
Step 3: Use the slope to find another point
The slope \(m = 1=\frac{1}{1}\), which means for a change of \(1\) unit in the \(x\) - direction (run), we have a change of \(1\) unit in the \(y\) - direction (rise). From \((0,2)\), moving \(1\) unit to the right (increase \(x\) by \(1\)) and \(1\) unit up (increase \(y\) by \(1\)), we get the point \((1,3)\). We can also move \(1\) unit to the left and \(1\) unit down to get \((- 1,1)\).
Step 4: Draw the line
Connect the points \((0,2)\), \((1,3)\) (or other points found) with a straight line.
Equation 2: \(y=-2x - 4\)
Step 1: Identify slope (\(m\)) and y - intercept (\(b\))
For \(y=-2x - 4\), comparing with \(y = mx + b\), we have \(m=-2\) (slope) and \(b = - 4\) (y - intercept).
Step 2: Plot the y - intercept
The y - intercept is at the point \((0,-4)\). Mark the point \((0,-4)\) on the coordinate plane.
Step 3: Use the slope to find another point
The slope \(m=-2=\frac{-2}{1}\), which means for a change of \(1\) unit in the \(x\) - direction (run), we have a change of \(- 2\) units in the \(y\) - direction (rise). From \((0,-4)\), moving \(1\) unit to the right (increase \(x\) by \(1\)) and \(2\) units down (decrease \(y\) by \(2\)), we get the point \((1,-6)\). We can also move \(1\) unit to the left and \(2\) units up to get \((-1,-2)\).
Step 4: Draw the line
Connect the points \((0,-4)\), \((1,-6)\) (or other points found) with a straight line.
Equation 3: \(y=\frac{2}{3}x\)
Step 1: Identify slope (\(m\)) and y - intercept (\(b\))
For \(y=\frac{2}{3}x\), we can write it as \(y=\frac{2}{3}x+0\). So \(m = \frac{2}{3}\) (slope) and \(b = 0\) (y - intercept).
Step 2: Plot the y - intercept
The y - intercept is at the point \((0,0)\) (the origin). Mark the point \((0,0)\) on the coordinate plane.
Step 3: Use the slope to find another point
The slope \(m=\frac{2}{3}\), which means for a change of \(3\) units in the \(x\) - direction (run), we have a change of \(2\) units in the \(y\) - direction (rise). From \((0,0)\), moving \(3\) units to the right (increase \(x\) by \(3\)) and \(2\) units up (increase \(y\) by \(2\)), we get the point \((3,2)\). We can also move \(3\) units to the left and \(2\) units down to get \((-3,-2)\).
Step 4: Draw the line
Connect the points \((0,0)\), \((3,2)\) (or other points found) with a straight line.
Equation 4: \(y=-\frac{1}{4}x + 3\)
Step 1: Identify slope (\(m\)) and y - intercept (\(b\))
For \(y=-\frac{1}{4}x + 3\), comparing with \(y = mx + b\), we have \(m=-\frac{1}{4}\) (slope) and \(b = 3\) (y - intercept).
Step 2: Plot the y - intercept
The y - intercept is at the point \((0,3)\). Mark the point \((0,3)\) on the coordinate plane.
Step 3: Use the slope to find another point
The slope \(m =-\frac{1}{4}=\frac{-1}{4}\), which means for a change of \(4\) units in the \(x\) - direction (run), we have a change of \(- 1\) unit in the \(y\) - direction (rise). From \((0,3)\), moving \(4\) units to the right (increase \(x\) by \(4\)) and \(1\) unit down (decrease \(y\) by \(1\)), we get the point \((4,2)\). We can also move \(4\) units to the left an…
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To graph the equations:
- For \(y = x+2\), plot \((0,2)\) and use slope \(1\) to draw the line.
- For \(y=-2x - 4\), plot \((0,-4)\) and use slope \(-2\) to draw the line.
- For \(y=\frac{2}{3}x\), plot \((0,0)\) and use slope \(\frac{2}{3}\) to draw the line.
- For \(y =-\frac{1}{4}x + 3\), plot \((0,3)\) and use slope \(-\frac{1}{4}\) to draw the line.