Question

graph the function.\\( r(x) = \

$$\begin{cases} x^2 - 1 & \\text{for } x \\leq 1 \\\\ 5x - 5 & \\text{for } x > 1 \\end{cases}$$

\\)\
part 1 of 5\
the first rule defines a \\( \boldsymbol{\text{parabola}} \\) with vertex \\( \boldsymbol{(0, -1)} \\).\
part: 1 / 5\
part 2 of 5\
since \\( x \leq 1 \\), the \\( \boldsymbol{\text{select}} \\) point \\( (\boldsymbol{\square}, \boldsymbol{\square}) \\) is graphed as a solid dot.

Explanation:

Step1: Find endpoint for $x\leq1$

Substitute $x=1$ into $r(x)=x^2-1$:
$r(1)=1^2 - 1 = 0$

Step2: Identify solid dot coordinates

The domain includes $x=1$, so the point is solid.

Answer:

The solid dot is at $(1, 0)$