Question

graph the function:
( g(x) = \frac{1}{2}x^2 )
plot five points on the graph of the function: one point with ( x = 0 ), two points with negative ( x )-values, and two points with positive ( x )-values. then click on the graph - a - function button.

Explanation:

Step1: Calculate x=0 point

Substitute $x=0$:
$g(0)=\frac{1}{2}(0)^2=0$
Point: $(0, 0)$

Step2: Calculate negative x points

Substitute $x=-2$:
$g(-2)=\frac{1}{2}(-2)^2=\frac{1}{2}(4)=2$
Point: $(-2, 2)$
Substitute $x=-4$:
$g(-4)=\frac{1}{2}(-4)^2=\frac{1}{2}(16)=8$
Point: $(-4, 8)$

Step3: Calculate positive x points

Substitute $x=2$:
$g(2)=\frac{1}{2}(2)^2=\frac{1}{2}(4)=2$
Point: $(2, 2)$
Substitute $x=4$:
$g(4)=\frac{1}{2}(4)^2=\frac{1}{2}(16)=8$
Point: $(4, 8)$

Answer:

Plot the following points and draw the parabola:

1. $(0, 0)$
2. $(-2, 2)$
3. $(-4, 8)$
4. $(2, 2)$
5. $(4, 8)$