Question

graph this function.
$y = 5(2)^x$
plot two points to graph the function.

Explanation:

Step1: Choose x=0, solve for y

Substitute $x=0$ into $y=5(2)^x$.
$y=5(2)^0 = 5\times1 = 5$
This gives the point $(0, 5)$.

Step2: Choose x=1, solve for y

Substitute $x=1$ into $y=5(2)^x$.
$y=5(2)^1 = 5\times2 = 10$
This gives the point $(1, 10)$.

Step3: Choose x=-1, solve for y (optional check)

Substitute $x=-1$ into $y=5(2)^x$.
$y=5(2)^{-1} = 5\times\frac{1}{2} = 2.5$
This gives the point $(-1, 2.5)$.

Answer:

Plot the points $(0, 5)$ and $(1, 10)$ on the coordinate grid, then draw a smooth exponential curve passing through these points (and extending upwards as $x$ increases, approaching the x-axis as $x$ decreases). The key plotted points are $(0, 5)$ and $(1, 10)$.