Question

graph the function $f(x) = 8x^2$. plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first. (graph with x-axis from -10 to 10 and f(x)-axis from -10 to 10)

Explanation:

Step1: Identify the vertex

For a quadratic function in the form $f(x)=ax^2$, the vertex is at $(0,0)$. Substitute $x=0$:
$f(0)=8(0)^2=0$

Step2: Find a second point

Choose $x=1$, substitute into the function:
$f(1)=8(1)^2=8$
This gives the point $(1,8)$. We can also use $x=-1$:
$f(-1)=8(-1)^2=8$, which gives $(-1,8)$

Answer:

1. Plot the vertex at $(0, 0)$.
2. Plot a second point at $(1, 8)$ (or $(-1, 8)$), then draw a parabola opening upward passing through these points.