Question

graph the function $f(x) = 3x^2$. plot the vertex. then plot another point on the parabola. if you make a mistake, you can erase your parabola by selecting the second point and placing it on top of the first.

Explanation:

Step1: Identify the vertex

For $f(x)=ax^2$, vertex is $(0,0)$.

Step2: Find a second point

Substitute $x=1$: $f(1)=3(1)^2=3$. Point: $(1,3)$.

Step3: Use symmetry for third point

Parabola is symmetric over y-axis. Point: $(-1,3)$.

Answer:

1. Plot the vertex at $(0, 0)$.
2. Plot the point $(1, 3)$ and its symmetric point $(-1, 3)$.
3. Draw a smooth upward-opening parabola through these points.