Question

graphing a quadratic function in vertex form
graph ( h(x) = 0.5(x + 2)^2 - 4 ) by following these steps
step 1: identify ( a ), ( h ), and ( k ).
( a = ) ( 0.5 ) ( h = ) ( -2 ) ( k = ) ( -4 )
step 2: plot the vertex at ( (-2, -4) ).
step 3: the axis of symmetry is the line
( x = -2 )
step 4: evaluate the function at two other ( x )-values:
( h(-4) = )

Explanation:

Step1: Substitute $x=-4$ into $h(x)$

$h(-4)=0.5(-4+2)^2 - 4$

Step2: Simplify inside parentheses

$h(-4)=0.5(-2)^2 - 4$

Step3: Calculate the squared term

$h(-4)=0.5\times4 - 4$

Step4: Compute multiplication then subtraction

$h(-4)=2 - 4$

Answer:

$-2$