Question

graphing a quadratic function in vertex form
graph ( h(x) = 0.5(x + 2)^2 - 4 ) by following these steps:
step 1: identify ( a ), ( h ), and ( k ).
( a = 0.5 ) ( h = -2 ) ( k = -4 )
step 2: plot the vertex at ( (-2, -4) ).
step 3: the axis of symmetry is the line
( x = ) dropdown with -2, 2, 4 as options
graph and table with x=-2, y=-4 shown

Explanation:

Step1: Recall vertex form rules

For quadratic $h(x)=a(x-h)^2+k$, axis of symmetry is $x=h$.

Step2: Match given function values

Given $h(x)=0.5(x+2)^2-4 = 0.5(x-(-2))^2-4$, so $h=-2$.

Answer:

$-2$