Question

match each polynomial function to its graph.
$f(x) = -x^3 - 9x^2 - 27x - 27 = -(x + 3)^3$
$g(x) = -x^3$
$f(x) = -x^3 - 9x^2 - 27x - 27$
$g(x) = -x^3$

Explanation:

2: Analyze $f(x) = -(x + 3)^3$
$f(x) = -(x + 3)^3$ has a root at $x=-3$ (since $-(-3 + 3)^3=0$). The left graph has a root at $x=-3$, so it is $f(x)$.

Answer:

2: Analyze $f(x) = -(x + 3)^3$
$f(x) = -(x + 3)^3$ has a root at $x=-3$ (since $-(-3 + 3)^3=0$). The left graph has a root at $x=-3$, so it is $f(x)$.