Question

match the image with its correct identity.

Explanation:

To solve this, we analyze each structure:

First Structure (\(\boldsymbol{\ce{CH3CH2CHCH2CH2CH2CHCH3}}\) with a \(\ce{CH3}\) branch)

• Count carbon atoms: The main chain (longest continuous C chain) has 8 carbons (parent chain: octane). The branch is a \(\ce{CH3}\) at carbon 3 (numbering from left, the branch is on the 3rd C). So it’s 3 - methyloctane (alkane, single bonds only).

Second Structure (\(\boldsymbol{\ce{CH3CH=CHCH2CH2CH2CHCH3}}\) with a \(\ce{CH3}\) branch)

• The double bond (\(\ce{C=C}\)) is at carbon 2 - 3 (numbering to give double bond lowest number). The main chain has 8 carbons (parent chain: octene, since it has a double bond). The branch is a \(\ce{CH3}\) at carbon 7. So it’s 7 - methyl - 2 - octene (alkene, has a \(\ce{C=C}\) bond).

Third Structure (\(\boldsymbol{\ce{CH3 - CH2 - Br}}\))

• This is a two - carbon chain (\(\ce{C2H5}\)) with a \(\ce{Br}\) substituent. So it’s bromoethane (alkyl halide, has a halogen (\(\ce{Br}\)) attached to an alkane chain).

If we assume the “identities” to match are likely alkane, alkene, and alkyl halide, we pair:

• The first (alkane, single bonds) → 3 - methyloctane (or “octane with methyl branch”).
• The second (alkene, double bond) → 7 - methyl - 2 - octene (or “octene with methyl and double bond”).
• The third (alkyl halide) → bromoethane (or “ethyl bromide”).

(Note: If the “identities” are labels like “alkane”, “alkene”, “alkyl halide”, the matches are:

• First structure: Alkane (3 - methyloctane)
• Second structure: Alkene (7 - methyl - 2 - octene)
• Third structure: Alkyl halide (bromoethane))

Answer:

To solve this, we analyze each structure:

First Structure (\(\boldsymbol{\ce{CH3CH2CHCH2CH2CH2CHCH3}}\) with a \(\ce{CH3}\) branch)

• Count carbon atoms: The main chain (longest continuous C chain) has 8 carbons (parent chain: octane). The branch is a \(\ce{CH3}\) at carbon 3 (numbering from left, the branch is on the 3rd C). So it’s 3 - methyloctane (alkane, single bonds only).

Second Structure (\(\boldsymbol{\ce{CH3CH=CHCH2CH2CH2CHCH3}}\) with a \(\ce{CH3}\) branch)

• The double bond (\(\ce{C=C}\)) is at carbon 2 - 3 (numbering to give double bond lowest number). The main chain has 8 carbons (parent chain: octene, since it has a double bond). The branch is a \(\ce{CH3}\) at carbon 7. So it’s 7 - methyl - 2 - octene (alkene, has a \(\ce{C=C}\) bond).

Third Structure (\(\boldsymbol{\ce{CH3 - CH2 - Br}}\))

• This is a two - carbon chain (\(\ce{C2H5}\)) with a \(\ce{Br}\) substituent. So it’s bromoethane (alkyl halide, has a halogen (\(\ce{Br}\)) attached to an alkane chain).

If we assume the “identities” to match are likely alkane, alkene, and alkyl halide, we pair:

• The first (alkane, single bonds) → 3 - methyloctane (or “octane with methyl branch”).
• The second (alkene, double bond) → 7 - methyl - 2 - octene (or “octene with methyl and double bond”).
• The third (alkyl halide) → bromoethane (or “ethyl bromide”).

(Note: If the “identities” are labels like “alkane”, “alkene”, “alkyl halide”, the matches are:

• First structure: Alkane (3 - methyloctane)
• Second structure: Alkene (7 - methyl - 2 - octene)
• Third structure: Alkyl halide (bromoethane))