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Question
- $y = -x + 4$ $y = 2x - 8$
Step1: Set the equations equal
Since both equations equal \( y \), set \( -x + 4 = 2x - 8 \)
Step2: Solve for \( x \)
Add \( x \) to both sides: \( 4 = 3x - 8 \)
Add 8 to both sides: \( 12 = 3x \)
Divide by 3: \( x = 4 \)
Step3: Find \( y \)
Substitute \( x = 4 \) into \( y = -x + 4 \): \( y = -4 + 4 = 0 \)
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The solution is \( x = 4 \), \( y = 0 \) (the point of intersection is \( (4, 0) \))