Question

1. $6\frac{1}{4} - 3\frac{9}{10}$

Explanation:

Step1: Convert to improper fractions

$6\frac{1}{4} = \frac{6\times4 + 1}{4} = \frac{25}{4}$, $3\frac{9}{10} = \frac{3\times10 + 9}{10} = \frac{39}{10}$

Step2: Find common denominator (20)

$\frac{25}{4} = \frac{25\times5}{4\times5} = \frac{125}{20}$, $\frac{39}{10} = \frac{39\times2}{10\times2} = \frac{78}{20}$

Step3: Subtract the fractions

$\frac{125}{20} - \frac{78}{20} = \frac{125 - 78}{20} = \frac{47}{20}$

Step4: Convert to mixed number

$\frac{47}{20} = 2\frac{7}{20}$

Answer:

$2\frac{7}{20}$ (or $\frac{47}{20}$)