Question

1. solve: \\(\frac{3^3 - (2^2 - 1)}{9 \times 2 \div 3}\\)

Explanation:

Step1: Calculate exponents and parentheses

First, calculate the exponents and the expression inside the parentheses. For the numerator: \(3^3 = 27\), \(2^2 = 4\), so \(2^2 - 1 = 4 - 1 = 3\). For the denominator: \(9\times2\div3\), we can also calculate step - by - step, but first let's handle the numerator. The numerator becomes \(27-3 = 24\).

Step2: Calculate the denominator

Now calculate the denominator: \(9\times2\div3\). According to the order of operations (multiplication and division have the same precedence, so we calculate from left to right), \(9\times2 = 18\), then \(18\div3 = 6\).

Step3: Divide numerator by denominator

Now we have the fraction \(\frac{24}{6}\). Dividing 24 by 6 gives us 4.

Answer:

4