Question

simplify.
\sqrt{3} \cdot \sqrt{5}

Explanation:

Step1: Recall the property of square roots: $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ for non - negative real numbers $a$ and $b$.

Here, $a = 3$ and $b = 5$. So we can apply this property to $\sqrt{3}\cdot\sqrt{5}$.

Step2: Apply the property

$\sqrt{3}\cdot\sqrt{5}=\sqrt{3\times5}=\sqrt{15}$

Answer:

$\sqrt{15}$