Question

the population p, in thousands, of a small city is given by the following function, where t is time in years. answer parts a) through c). p(t)=\frac{500t}{2t^{2}+9} a) find the growth rate. the growth rate is \frac{4500 - 1000t^{2}}{(2t^{2}+9)^{2}} b) find the population after 11 yr. the population is after 11 years (round to the nearest integer as needed.)

Explanation:

Step1: Substitute t = 11 into P(t)

$P(11)=\frac{500\times11}{2\times11^{2}+9}$

Step2: Calculate the value

$P(11)=\frac{5500}{2\times121 + 9}=\frac{5500}{242+9}=\frac{5500}{251}\approx22$

Answer:

22