Question

practice with quadratic functions in vertex form. what is the axis of symmetry and vertex for the function $f(x) = 3(x - 2)^2 + 4$? $x = \square$ vertex: $(\square, \square)$

Explanation:

Step1: Recall vertex form rules

A quadratic function in vertex form is $f(x)=a(x-h)^2+k$, where the axis of symmetry is $x=h$, and the vertex is $(h,k)$.

Step2: Identify h and k values

For $f(x)=3(x-2)^2+4$, $h=2$ and $k=4$.

Step3: Find axis of symmetry

Axis of symmetry is $x=h$, so $x=2$.

Step4: Find vertex coordinates

Vertex is $(h,k)$, so $(2,4)$.

Answer:

$x=2$
Vertex: $(2, 4)$