Question

0.4 properties of algebra: problem (1 point) evaluate each algebraic expression for the given value(s): a) $4 + 2(x - 5)^3$, for $x = 7$ answer: \boxed{} b) $x^2 - 4(x - y)$, for $x = 8$ and $y = 3$ answer: \boxed{} note: you can earn partial credit on this problem. preview my answers submit answers you have attempted this problem 0 times. you have unlimited attempts remaining. email instructor

Explanation:

Part (a)

Step1: Substitute \( x = 7 \) into the expression

Substitute \( x = 7 \) into \( 4 + 2(x - 5)^3 \), we get \( 4 + 2(7 - 5)^3 \).

Step2: Simplify the parentheses

Calculate \( 7 - 5 = 2 \), so the expression becomes \( 4 + 2(2)^3 \).

Step3: Calculate the exponent

Calculate \( 2^3 = 8 \), so the expression becomes \( 4 + 2\times8 \).

Step4: Multiply

Calculate \( 2\times8 = 16 \), so the expression becomes \( 4 + 16 \).

Step5: Add

Calculate \( 4 + 16 = 20 \).

Step1: Substitute \( x = 8 \) and \( y = 3 \) into the expression

Substitute \( x = 8 \) and \( y = 3 \) into \( x^2 - 4(x - y) \), we get \( 8^2 - 4(8 - 3) \).

Step2: Simplify the parentheses

Calculate \( 8 - 3 = 5 \), so the expression becomes \( 8^2 - 4\times5 \).

Step3: Calculate the exponent

Calculate \( 8^2 = 64 \), so the expression becomes \( 64 - 4\times5 \).

Step4: Multiply

Calculate \( 4\times5 = 20 \), so the expression becomes \( 64 - 20 \).

Step5: Subtract

Calculate \( 64 - 20 = 44 \).

Answer:

\( 20 \)

Part (b)