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question 2 of 12 (1 point) | question attempt: 2 of unlimited
$\
$$\begin{cases} y=\\frac{1}{2}x-2 \\\\ x-2y=0 \\end{cases}$$
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o solution\ or \infinitely many\ solutions.
Step1: Rearrange second equation
Solve $x-2y=0$ for $y$:
$$x-2y=0 \implies -2y = -x \implies y=\frac{1}{2}x$$
Step2: Compare the two linear equations
First equation: $y=\frac{1}{2}x - 2$
Second equation (rearranged): $y=\frac{1}{2}x$
These are parallel lines (same slope $\frac{1}{2}$, different y-intercepts: $-2$ and $0$). Parallel lines never intersect.
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