Question

question 6 of 20 (1 point) | question attempt: 1 of unlimited
incorrect
your answer is incorrect.
graph the inequality
-3x - 2y < -6
try again

Explanation:

Step1: Rewrite to slope-intercept form

Start with the inequality:
$$-3x - 2y < -6$$
Add $3x$ to both sides:
$$-2y < 3x - 6$$
Divide by $-2$ (reverse inequality sign):
$$y > -\frac{3}{2}x + 3$$

Step2: Identify boundary line

The boundary is $y = -\frac{3}{2}x + 3$.

• Y-intercept: $(0, 3)$
• X-intercept: Set $y=0$:

$$0 = -\frac{3}{2}x + 3 \implies \frac{3}{2}x = 3 \implies x=2$$
So x-intercept is $(2, 0)$.
Use a dashed line (since inequality is $>$).

Step3: Determine shaded region

Test point $(0,0)$ in $y > -\frac{3}{2}x + 3$:
$$0 > 0 + 3 \implies 0 > 3$$
This is false, so shade the region above the dashed line.

Answer:

1. Draw a dashed line through points $(0, 3)$ and $(2, 0)$ (representing $y = -\frac{3}{2}x + 3$).
2. Shade the area above this dashed line.