Question

question
find the slope of the secant line between x = 2 and x = 5 on the graph of the function f(x)=x^{2}-2x + 5.
provide your answer below:
m_{sec}=□

Explanation:

Step1: Find f(2)

$f(2)=2^{2}-2\times2 + 5=4 - 4+5 = 5$

Step2: Find f(5)

$f(5)=5^{2}-2\times5 + 5=25-10 + 5=20$

Step3: Use slope formula

The slope formula for the secant line between $(x_1,f(x_1))$ and $(x_2,f(x_2))$ is $m=\frac{f(x_2)-f(x_1)}{x_2 - x_1}$. Here $x_1 = 2,x_2=5,f(x_1)=5,f(x_2)=20$. So $m=\frac{20 - 5}{5 - 2}=\frac{15}{3}=5$

Answer:

5