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Question
question
given the definitions of f(x) and g(x) below, find the value of g(f(0)).
$f(x) = x^2 - 6x + 1$
$g(x) = 5x + 15$
answer attempt 1 out of 3
Step1: Find f(0)
Substitute \( x = 0 \) into \( f(x)=x^{3}-6x + 1 \).
\( f(0)=0^{3}-6\times0 + 1=1 \)
Step2: Find g(f(0))
Since \( f(0) = 1 \), substitute \( x = 1 \) into \( g(x)=5x + 15 \).
\( g(1)=5\times1+15 = 20 \)
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20