Question

question let $h(x)=\frac{f(x)}{g(x)}$, where $f(4)= - 3,f(4)= - 5,g(4)=5$, and $g(4)= - 1$. what is $h(4)$? do not include \$h(4)=\$ in your answer. for example, if you found $h(4)=7$, you would enter 7. provide your answer below:

Explanation:

Step1: Apply quotient - rule

The quotient - rule states that if $h(x)=\frac{f(x)}{g(x)}$, then $h^{\prime}(x)=\frac{f^{\prime}(x)g(x)-f(x)g^{\prime}(x)}{g(x)^2}$.

Step2: Substitute $x = 4$

$h^{\prime}(4)=\frac{f^{\prime}(4)g(4)-f(4)g^{\prime}(4)}{g(4)^2}=\frac{(-5)\times5-(-3)\times(-1)}{5^2}=\frac{-25 - 3}{25}=\frac{-28}{25}=-1.12$

Answer:

$-1.12$