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question 9 · 1 point given f(x) below, find f(x). f(x)=\int_{3}^{x}-\frac{3}{2t + 7}dt provide your answer below: f(x)=□
Step1: Apply the fundamental theorem of calculus
If $F(x)=\int_{a}^{x}f(t)dt$, then $F^{\prime}(x)=f(x)$. Here, $a = 3$ and $f(t)=-\frac{3}{2t + 7}$.
Step2: Find the derivative of $F(x)$
Substitute $t=x$ into $f(t)$. So $F^{\prime}(x)=-\frac{3}{2x+7}$.
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$-\frac{3}{2x + 7}$