Question

question 3 of 6, step 1 of 3
an sat prep course claims to increase student scores by more than 60 points, on average. to test this claim, 9 students who have previously taken the sat are randomly chosen to take the prep course. their sat scores before and after completing the prep course are listed in the following table. test the claim at the 0.10 level of significance assuming that the population distribution of the paired differences is approximately normal. let d = (scores after completing the prep course) - (scores before completing the prep course).
sat scores

before prep course	1380	1120	1370	1490	1440	1050	1190	1190	1350
after prep course	1550	1350	1470	1540	1460	1270	1240	1300	1510

copy data
step 1 of 3: state the null and alternative hypotheses for the test. fill in the blank below.
$h_0:mu_d = 60$
$h_a:mu_d$ ____ 60
answer
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Explanation:

Step1: Identify the claim

The claim is that the prep - course increases student scores by more than 60 points. So the alternative hypothesis should reflect this 'greater than' relationship.

Step2: Determine the alternative hypothesis

Since the null hypothesis \(H_0:\mu_d = 60\), and the claim is that the mean difference \(\mu_d\) is greater than 60, the alternative hypothesis \(H_a:\mu_d>60\).

Answer: