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Question
question. suppose that the length $l$, width $w$, and perimeter $p$ of a rectangle are differentiable functions of $t$. suppose also that the length is always three times and twenty - two more than the width. write an equation that relates $\frac{dp}{dt}$ to $\frac{dw}{dt}$. enter your answer using exact values. provide your answer below: $\frac{dp}{dt}=square\frac{dw}{dt}$
Step1: Write perimeter formula
The perimeter formula of a rectangle is $P = 2(l + w)$.
Step2: Substitute the relationship of $l$ and $w$
Given $l=3w + 22$, so $P = 2((3w + 22)+w)=2(4w + 22)=8w + 44$.
Step3: Differentiate both sides with respect to $t$
Using the chain - rule, $\frac{dP}{dt}=\frac{d}{dt}(8w + 44)$. Since $\frac{d}{dt}(8w + 44)=8\frac{dw}{dt}+0$, we can solve for $\frac{dP}{dt}/\frac{dw}{dt}$.
Dividing both sides of $\frac{dP}{dt}=8\frac{dw}{dt}$ by $\frac{dw}{dt}$ (assuming $\frac{dw}{dt}
eq0$), we get $\frac{\frac{dP}{dt}}{\frac{dw}{dt}} = 8$.
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