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question: what is lim x→+∞ s(x)? s(x)=4ex10x2 select the correct answer below: 0 5/2 2/5 +∞ -∞
Step1: Apply L'Hopital's rule
Since $\lim_{x
ightarrow+\infty}\frac{10x^{2}}{4e^{x}}$ is in the $\frac{\infty}{\infty}$ - form, by L'Hopital's rule, $\lim_{x
ightarrow+\infty}\frac{10x^{2}}{4e^{x}}=\lim_{x
ightarrow+\infty}\frac{20x}{4e^{x}}$.
Step2: Apply L'Hopital's rule again
The limit $\lim_{x
ightarrow+\infty}\frac{20x}{4e^{x}}$ is still in the $\frac{\infty}{\infty}$ - form. So, $\lim_{x
ightarrow+\infty}\frac{20x}{4e^{x}}=\lim_{x
ightarrow+\infty}\frac{20}{4e^{x}}$.
Step3: Evaluate the limit
As $x
ightarrow+\infty$, $e^{x}
ightarrow+\infty$. Then $\lim_{x
ightarrow+\infty}\frac{20}{4e^{x}} = 0$.
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