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Question
if (y = sin^{3}x), then (\frac{dy}{dx}=)
Step1: Apply chain - rule
Let $u = \sin x$, then $y = u^{3}$. The chain - rule states that $\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}$.
Step2: Differentiate $y$ with respect to $u$
If $y = u^{3}$, then $\frac{dy}{du}=3u^{2}$.
Step3: Differentiate $u$ with respect to $x$
If $u=\sin x$, then $\frac{du}{dx}=\cos x$.
Step4: Substitute $u$ back and find $\frac{dy}{dx}$
Substitute $u = \sin x$ into $\frac{dy}{du}$ and multiply by $\frac{du}{dx}$. We get $\frac{dy}{dx}=3\sin^{2}x\cdot\cos x$.
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$3\sin^{2}x\cos x$