Question

solve each problem paying careful attention to the order of operations.
$(12 - 4) \div 2$
choose
$9 + 2 - 6$
choose
$3 + 2 \times 7$
choose
$10 \div 2 - 1$
choose
$9 - 6 \div 2$
choose
$24 \div 2 - 8$
choose
$(2 + 6) \times 7$
choose
$12 - 12 \div 3$
choose
$(4 + 6) \div 5$
choose
$12 - 3 + 9$
choose

Explanation:

Step1: Solve parentheses first

$(12 - 4) \div 2 = 8 \div 2$

Step2: Perform division

$8 \div 2 = 4$

Step1: Left-to-right addition/subtraction

$9 + 2 - 6 = 11 - 6$

Step2: Final subtraction

$11 - 6 = 5$

Step1: Perform multiplication first

$3 + 2 \times 7 = 3 + 14$

Step2: Perform addition

$3 + 14 = 17$

Step1: Perform division first

$10 \div 2 - 1 = 5 - 1$

Step2: Perform subtraction

$5 - 1 = 4$

Step1: Perform division first

$9 - 6 \div 2 = 9 - 3$

Step2: Perform subtraction

$9 - 3 = 6$

Step1: Perform division first

$24 \div 2 - 8 = 12 - 8$

Step2: Perform subtraction

$12 - 8 = 4$

Step1: Solve parentheses first

$(2 + 6) \times 7 = 8 \times 7$

Step2: Perform multiplication

$8 \times 7 = 56$

Step1: Perform division first

$12 - 12 \div 3 = 12 - 4$

Step2: Perform subtraction

$12 - 4 = 8$

Step1: Solve parentheses first

$(4 + 6) \div 5 = 10 \div 5$

Step2: Perform division

$10 \div 5 = 2$

Step1: Left-to-right addition/subtraction

$12 - 3 + 9 = 9 + 9$

Step2: Perform addition

$9 + 9 = 18$

Answer:

$(12 - 4) \div 2 = 4$
$9 + 2 - 6 = 5$
$3 + 2 \times 7 = 17$
$10 \div 2 - 1 = 4$
$9 - 6 \div 2 = 6$
$24 \div 2 - 8 = 4$
$(2 + 6) \times 7 = 56$
$12 - 12 \div 3 = 8$
$(4 + 6) \div 5 = 2$
$12 - 3 + 9 = 18$