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standard deviation fiona recorded the number of miles she biked each da…

Question

standard deviation
fiona recorded the number of miles she biked each day last week as shown.
4, 7, 4, 10, 5
the mean is given by \\( \mu = 6 \\). which equation shows the variance for the number of miles fiona biked last week?
\\( s^2 = \frac{(4 - 6)^2 + (7 - 6)^2 + (4 - 6)^2 + (10 - 6)^2 + (5 - 6)^2}{6} \\)
\\( \sigma^2 = \frac{(4 - 6)^2 + (7 - 6)^2 + (4 - 6)^2 + (10 - 6)^2 + (5 - 6)^2}{5} \\)
\\( s = \sqrt{\frac{(4 - 6)^2 + (7 - 6)^2 + (4 - 6)^2 + (10 - 6)^2 + (5 - 6)^2}{4}} \\)
\\( \sigma = \sqrt{\frac{(4 - 6)^2 + (7 - 6)^2 + (4 - 6)^2 + (10 - 6)^2 + (5 - 6)^2}{5}} \\)

Explanation:

Step1: Recall Variance Formula

Variance for a population (denoted by \(\sigma^2\)) is calculated as the average of the squared differences from the Mean. The formula is \(\sigma^2=\frac{\sum_{i = 1}^{n}(x_i-\mu)^2}{n}\), where \(n\) is the number of data points, \(x_i\) are the data points, and \(\mu\) is the mean.

Step2: Identify Data Points and \(n\)

The data points are \(4,7,4,10,5\), so \(n = 5\). The mean \(\mu=6\).

Step3: Analyze Each Option

  • Option 1: Uses \(s^2\) (sample variance) and divides by 6, but \(n = 5\) and we use population variance here (since we have all data of the week), so wrong.
  • Option 2: Uses \(\sigma^2\) (population variance), sums \((4 - 6)^2+(7 - 6)^2+(4 - 6)^2+(10 - 6)^2+(5 - 6)^2\) (squared differences from mean) and divides by \(n = 5\), which matches the formula.
  • Option 3: Calculates standard deviation (\(s\)) and has wrong denominator, so wrong.
  • Option 4: Calculates standard deviation (\(\sigma\)) instead of variance, so wrong.

Answer:

\(\boldsymbol{\sigma^2=\frac{(4 - 6)^2+(7 - 6)^2+(4 - 6)^2+(10 - 6)^2+(5 - 6)^2}{5}}\) (the second option)