Question

suppose you flip two coins. what is the probability of getting at most one heads? give your answer as a reduced fraction.

Explanation:

Step1: List all possible outcomes

When flipping two coins, the sample - space $S=\{HH, HT, TH, TT\}$, so $n(S) = 4$.

Step2: List favorable outcomes

The event of getting at most one heads means getting 0 heads or 1 head. The favorable outcomes are $\{HT, TH, TT\}$, so $n(E)=3$.

Step3: Calculate the probability

The probability formula is $P(E)=\frac{n(E)}{n(S)}$. Substituting the values, we get $P(E)=\frac{3}{4}$.

Answer:

$\frac{3}{4}$