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triangle xyz is rotated to create the image triangle xyz. which rules c…

Question

triangle xyz is rotated to create the image triangle xyz.
which rules could describe the rotation? select two options.
$r_{0, 90\degree}$
$r_{0, 180\degree}$
$r_{0, 270\degree}$
$(x, y) \to (-y, x)$
$(x, y) \to (-x, -y)$

Explanation:

Step1: Identify coordinates of original points

First, find coordinates of \( X, Y, Z \):

  • \( X(-2, 2) \), \( Y(1, 2) \), \( Z(0, 4) \)

Coordinates of \( X', Y', Z' \):

  • \( X'(2, -2) \), \( Y'(-1, -2) \), \( Z'(0, -4) \)

Step2: Analyze rotation rules

Rule 1: \( R_{0, 180^\circ} \) or \( (x, y) \to (-x, -y) \)

For a \( 180^\circ \) rotation about the origin, the rule is \( (x, y) \to (-x, -y) \).

  • Test \( X(-2, 2) \): \( (-(-2), -2) = (2, -2) \) (matches \( X' \))
  • Test \( Y(1, 2) \): \( (-1, -2) \) (matches \( Y' \))
  • Test \( Z(0, 4) \): \( (0, -4) \) (matches \( Z' \))
Rule 2: Wait, no—wait, initial analysis: Wait, \( 90^\circ \) rotation? No, \( 90^\circ \) clockwise is \( (x,y)\to(y,-x) \), counterclockwise is \( (x,y)\to(-y,x) \). Wait, no—wait the \( 180^\circ \) and the \( (x,y)\to(-x,-y) \) are same as \( R_{0, 180^\circ} \). Wait, but also, wait the \( 180^\circ \) rotation and the \( (x,y)\to(-x,-y) \) are equivalent. Wait, but the options: \( R_{0, 180^\circ} \) and \( (x, y) \to (-x, -y) \) are correct? Wait no, wait the \( 180^\circ \) rotation is \( R_{0, 180^\circ} \), and the coordinate rule \( (x, y) \to (-x, -y) \). Wait, but also, wait the other option: Wait, no—wait the \( 90^\circ \) counterclockwise is \( (x,y)\to(-y,x) \), but let's check:

Wait, \( X(-2,2) \): \( (-2,2) \to (-2, -2) \)? No. Wait, no, \( 180^\circ \) is \( (-x,-y) \). Let's recheck:

For \( X(-2,2) \): \( -x = 2 \), \( -y = -2 \) → \( (2, -2) \) (matches \( X' \))

For \( Y(1,2) \): \( -x = -1 \), \( -y = -2 \) → \( (-1, -2) \) (matches \( Y' \))

For \( Z(0,4) \): \( -x = 0 \), \( -y = -4 \) → \( (0, -4) \) (matches \( Z' \))

So \( R_{0, 180^\circ} \) (which is \( (x,y)\to(-x,-y) \)) and \( (x, y) \to (-x, -y) \) are correct? Wait, no—the options are \( R_{0,90^\circ} \), \( R_{0,180^\circ} \), \( R_{0,270^\circ} \), \( (x,y)\to(-y,x) \), \( (x,y)\to(-x,-y) \).

Wait, \( R_{0, 180^\circ} \) is the rotation notation for \( 180^\circ \) about origin, and \( (x, y) \to (-x, -y) \) is the coordinate rule for \( 180^\circ \) rotation. So these two are equivalent. So the correct options are \( R_{0, 180^\circ} \) and \( (x, y) \to (-x, -y) \).

Wait, but let's confirm:

  • \( R_{0, 180^\circ} \) means rotation 180 degrees about origin.
  • The coordinate transformation for \( 180^\circ \) rotation is \( (x, y) \to (-x, -y) \).

Thus, the two correct options are \( R_{0, 180^\circ} \) and \( (x, y) \to (-x, -y) \).

Answer:

B. \( R_{0, 180^\circ} \)
E. \( (x, y) \to (-x, -y) \)

(Note: Assuming options are labeled as:
A. \( R_{0, 90^\circ} \)
B. \( R_{0, 180^\circ} \)
C. \( R_{0, 270^\circ} \)
D. \( (x, y) \to (-y, x) \)
E. \( (x, y) \to (-x, -y) \))