Question

type the correct answer in each box. functions h and k are inverse functions, and both are defined for all real numbers. using this relationship, what is the value of each function composition? \\((h \circ k)(3) = \square\\) \\((k \circ h)(-4b) = \square\\)

Explanation:

Step1: Recall inverse function rule

For inverse functions \(h\) and \(k\), \((h \circ k)(x) = x\)

Step2: Substitute \(x=3\)

\((h \circ k)(3) = 3\)

Step3: Recall inverse function rule

For inverse functions \(h\) and \(k\), \((k \circ h)(x) = x\)

Step4: Substitute \(x=-4b\)

\((k \circ h)(-4b) = -4b\)

Answer:

\((h \circ k)(3) = 3\)
\((k \circ h)(-4b) = -4b\)