Question

use your calculator to evaluate the integral below.\\(\int_{2.4}^{9.3} \frac{x + 7}{x^3 + 8} dx = \\)\
if your answer is a decimal, round to 3 places after the decimal.\
remember: for trig functions you must be in radian mode.\
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question 2\
use your calculator to evaluate the integral below.\\(\int_{5}^{6} \frac{10x - 10}{x^2 - 1x - 6} dx = \\)\
if your answer is a decimal, round to 3 places after the decimal.\
remember: for trig functions you must be in radian mode.\
question help: message instructor

Explanation:

Step1: Evaluate first definite integral

Using a calculator in radian mode, compute $\int_{2.4}^{0.3} \frac{x+7}{x^3+8} dx$. Note that reversing the limits changes the sign: $\int_{2.4}^{0.3} f(x)dx = -\int_{0.3}^{2.4} f(x)dx$.
$\int_{2.4}^{0.3} \frac{x+7}{x^3+8} dx \approx -0.927$

Step2: Evaluate second definite integral

First simplify the integrand (or use calculator directly): $\int_{5}^{6} \frac{10x-10}{x^2 - x - 6} dx$. Recognize it is a logarithmic integral (substitute $u=x^2-x-6$, $du=(2x-1)dx$, so $10x-10=5(2x-2)=5(2x-1)-5$, but calculator can compute directly.
$\int_{5}^{6} \frac{10x-10}{x^2 - x - 6} dx \approx 1.609$

Answer:

$\int_{2.4}^{0.3} \frac{x+7}{x^3+8} dx = -0.927$
$\int_{5}^{6} \frac{10x-10}{x^2 - x - 6} dx = 1.609$