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use the drawing tools to form the correct answer on the graph. graph th…

Question

use the drawing tools to form the correct answer on the graph. graph the line that represents this equation: y = -5x + 3

Explanation:

Step1: Identify the y-intercept

The equation is in slope - intercept form \(y = mx + b\), where \(b\) is the y - intercept. For the equation \(y=-5x + 3\), when \(x = 0\), \(y=3\). So the line passes through the point \((0,3)\).

Step2: Find another point using the slope

The slope \(m=-5=\frac{-5}{1}\). Starting from the point \((0,3)\), we move down 5 units (because the numerator of the slope is - 5, which represents a decrease in the y - value) and 1 unit to the right (because the denominator of the slope is 1, which represents an increase in the x - value). So from \((0,3)\), moving down 5 units gives \(y = 3-5=-2\) and moving right 1 unit gives \(x=0 + 1 = 1\). So another point on the line is \((1,-2)\).

Step3: Draw the line

Using the two points \((0,3)\) and \((1,-2)\) (or any other points found using the slope - intercept form), we can draw the line. We can also use the line tool to connect the points on the graph.

(Note: Since this is a graphing problem, the final answer is the graph of the line \(y=-5x + 3\) passing through the points like \((0,3)\) and \((1,-2)\) (and other points obtained by using the slope) on the coordinate plane.)

Answer:

Step1: Identify the y-intercept

The equation is in slope - intercept form \(y = mx + b\), where \(b\) is the y - intercept. For the equation \(y=-5x + 3\), when \(x = 0\), \(y=3\). So the line passes through the point \((0,3)\).

Step2: Find another point using the slope

The slope \(m=-5=\frac{-5}{1}\). Starting from the point \((0,3)\), we move down 5 units (because the numerator of the slope is - 5, which represents a decrease in the y - value) and 1 unit to the right (because the denominator of the slope is 1, which represents an increase in the x - value). So from \((0,3)\), moving down 5 units gives \(y = 3-5=-2\) and moving right 1 unit gives \(x=0 + 1 = 1\). So another point on the line is \((1,-2)\).

Step3: Draw the line

Using the two points \((0,3)\) and \((1,-2)\) (or any other points found using the slope - intercept form), we can draw the line. We can also use the line tool to connect the points on the graph.

(Note: Since this is a graphing problem, the final answer is the graph of the line \(y=-5x + 3\) passing through the points like \((0,3)\) and \((1,-2)\) (and other points obtained by using the slope) on the coordinate plane.)