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use the figure to answer the question. select all of the statements tha…

Question

use the figure to answer the question.
select all of the statements that are sufficient to determine that $\triangle jlm$ is isosceles?
\\(\square\\) a. \\(jk = kl\\)
\\(\square\\) b. \\(jm = ml\\)
\\(\square\\) c. \\(jl = mk\\)
\\(\square\\) d. \\(m\angle mjk = m\angle mlk\\)
\\(\square\\) e. \\(m\angle mjl = m\angle jml\\)
\\(\square\\) f. \\(m\angle jmk = m\angle lmk\\)

Explanation:

Step1: Recall isosceles triangle definition

A triangle is isosceles if it has at least two equal sides or two equal base angles.

Step2: Analyze Option A

$JK=KL$ means $MK$ is a median. If a median from the apex is also perpendicular (implied by the figure's structure, and by the Isosceles Triangle Theorem converse: a median to the base of a triangle that bisects the base implies the triangle is isosceles if the line is from the apex), this confirms $\triangle JLM$ has $JM=ML$.

Step3: Analyze Option B

$JM=ML$ directly gives two equal sides, so $\triangle JLM$ is isosceles by definition.

Step4: Analyze Option C

$JL=MK$ is a side equality between the base and a segment from the apex to the base; this does not imply two sides or angles of $\triangle JLM$ are equal, so it is insufficient.

Step5: Analyze Option D

$m\angle MJK = m\angle MLK$: These are angles at $K$, not the base angles of $\triangle JLM$. This does not confirm equal sides/angles of the triangle, so it is insufficient.

Step6: Analyze Option E

$m\angle MJL = m\angle JML$: These are two equal angles of $\triangle JLM$, so by the Converse of the Base Angles Theorem, the sides opposite them ($ML$ and $JM$) are equal, making the triangle isosceles.

Step7: Analyze Option F

$m\angle JMK = m\angle LMK$ means $MK$ bisects $\angle JML$. By the Converse of the Angle Bisector Theorem for triangles, if a line from the apex bisects the apex angle and meets the base, the triangle is isosceles (the two sides $JM$ and $ML$ are equal).

Answer:

A. $JK = KL$, B. $JM = ML$, E. $m\angle MJL = m\angle JML$, F. $m\angle JMK = m\angle LMK$