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what is the solution to the problem shown? \\(\\begin{array}{r}\\ 4,775…

Question

what is the solution to the problem shown?
\\(\

$$\begin{array}{r}\\ 4,775 \\\\ +\\ \\ \\ 123 \\\\ \\hline \\end{array}$$

\\)
a. 6,005
b. 4,798
c. 4,652
d. 4,898

Explanation:

Step1: Add the two numbers

We need to calculate \( 4775 + 123 \).
First, add the units place: \( 5 + 3 = 8 \).
Then, add the tens place: \( 7 + 2 = 9 \).
Next, add the hundreds place: \( 7 + 1 = 8 \).
The thousands place remains \( 4 \).
So, \( 4775 + 123 = 4898 \)? Wait, no, wait. Wait, 4775 + 123: let's do it properly. 4775 + 100 = 4875, 4875 + 20 = 4895, 4895 + 3 = 4898? Wait, no, that's not right. Wait, 4775 + 123: 4775 + 123. Let's add digit by digit:

Units: 5 + 3 = 8

Tens: 7 + 2 = 9

Hundreds: 7 + 1 = 8

Thousands: 4

So 4 (thousands), 8 (hundreds), 9 (tens), 8 (units) → 4898? Wait, but let's check again. 4775 + 123: 4775 + 100 = 4875, 4875 + 20 = 4895, 4895 + 3 = 4898. Yes. Wait, but the options: D is 4,898. Wait, but let me check again. Wait, 4775 + 123: 4775 + 123. Let's do 4775 + 123:

4775

+  123

------

Start from the rightmost digit (units place):

5 + 3 = 8 (units place)

7 (tens place of 4775) + 2 (tens place of 123) = 9 (tens place)

7 (hundreds place of 4775) + 1 (hundreds place of 123) = 8 (hundreds place)

4 (thousands place of 4775) + 0 (thousands place of 123) = 4 (thousands place)

So the result is 4 (thousands), 8 (hundreds), 9 (tens), 8 (units) → 4898. Wait, but option D is 4,898. Wait, but let me check again. Wait, 4775 + 123: 4775 + 123 = 4898. Yes. So the correct answer is D.

Wait, but wait, maybe I made a mistake. Wait, 4775 + 123: 4775 + 123. Let's calculate 4775 + 100 = 4875, 4875 + 20 = 4895, 4895 + 3 = 4898. Yes. So the answer is D.

Answer:

D. 4,898