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2. what is the weight(in pounds) of the current ball that is dropped ea…

Question

  1. what is the weight(in pounds) of the current ball that is dropped each year? 475×25

Explanation:

Step1: Multiply 475 by 25

To find the product of 475 and 25, we can use the standard multiplication algorithm.
First, multiply 475 by 5: \(475\times5 = 2375\)
Then, multiply 475 by 20: \(475\times20 = 9500\)

Step2: Add the two results

Now, add the two products together: \(2375 + 9500 = 11875\)

Answer:

The weight of the current ball is 11875 pounds.