Question

which integer is closest to (sqrt3{-26})?

Explanation:

Step1: Identify nearby perfect cubes

$(-3)^3 = -27$, $(-2)^3 = -8$

Step2: Compare distances to $\sqrt[3]{-26}$

Distance to $-3$: $|-26 - (-27)| = 1$
Distance to $-2$: $|-26 - (-8)| = 18$

Answer:

$-3$